Proof: We'll prove , since follows by symmetry. Suppose first that is a prime ideal. Let so that , the zero ideal of . Then if is the projection, consider , . Then (since is a ring homomorphism), so that without loss of generality , and hence . Suppose now that is a prime ring. Let then such that . We use the bar notation ( being the projection) for . Then we get that is zero for all . Then define the ideals and , so that then , hence without loss of generality and hence and thus . Suppose now that 5. holds, and let be left ideals such that . Suppose that there existed so that and . Then still , a contradiction. Note finally that is trivial.