计算激发 CO 从基态振动到第一振动态所需的激发光子的频率 (k=1860 N/m)。
v 0 = 1 2 π ⋅ ( k μ ) 1 2 w h e r e μ = m 1 ⋅ m 2 m 1 + m 2 {\displaystyle v_{0}={\frac {1}{2\pi }}\cdot {\biggl (}{\frac {k}{\mu }}{\biggr )}^{\frac {1}{2}}\qquad where\ \mu ={\frac {m_{1}\cdot m_{2}}{m_{1}+m_{2}}}}
C= 12.011u, O =15.999u
将这些值代入约化质量方程
μ = 12.011 u ⋅ 15.999 u 12.011 u + 15.999 u {\displaystyle \mu ={\frac {12.011u\cdot 15.999u}{12.011u+15.999u}}}
μ = 6.861 u {\displaystyle \mu =6.861u}
将约化质量从 u 单位转换为 kg
1 u = 1.66054 × 10 − 27 k g {\displaystyle 1u=1.66054\times 10^{-27}kg}
μ = 1.139 × 10 − 26 k g {\displaystyle \mu =1.139\times 10^{-26}kg}
v 0 = 1 2 π ⋅ ( 1860 N / m 1.139 × 10 − 26 k g ) 1 2 {\displaystyle v_{0}={\frac {1}{2\pi }}\cdot {\biggl (}{\frac {1860N/m}{1.139\times 10^{-26}kg}}{\biggr )}^{\frac {1}{2}}\qquad }
∴ v 0 = 6.43 × 10 13 s − 1 {\displaystyle \therefore v_{0}=6.43\times 10^{13}s^{-1}}