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1
习题1A
切换习题1A小节
1.1
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切换目录
数学课本解答/纯数学1/第一章
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来自Wikibooks,开放世界中的开放书籍
<
数学课本解答
|
纯数学1
习题1A
[
编辑
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编辑源代码
]
1.
[
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编辑源代码
]
9
x
{\displaystyle 9x}
p
−
13
{\displaystyle p-13}
k
−
4
m
+
4
n
{\displaystyle k-4m+4n}
0
{\displaystyle 0}
r
+
2
s
−
15
t
{\displaystyle r+2s-15t}
2.
[
编辑
|
编辑源代码
]
4
(
x
+
2
y
)
{\displaystyle 4(x+2y)}
3
(
4
a
+
5
b
−
6
c
)
{\displaystyle 3(4a+5b-6c)}
12
(
6
f
+
3
g
−
4
h
)
{\displaystyle 12(6f+3g-4h)}
p
(
p
−
q
+
r
)
{\displaystyle p(p-q+r)}
12
k
(
k
+
12
m
−
6
n
)
{\displaystyle 12k(k+12m-6n)}
3.
[
编辑
|
编辑源代码
]
28
(
x
+
y
)
{\displaystyle 28(x+y)}
7
b
+
13
c
{\displaystyle 7b+13c}
−
p
+
24
q
+
33
r
{\displaystyle -p+24q+33r}
2
(
5
l
+
3
w
−
h
)
{\displaystyle 2(5l+3w-h)}
2
(
w
+
2
v
)
{\displaystyle 2(w+2v)}
4.
[
编辑
|
编辑源代码
]
2
a
b
{\displaystyle 2ab}
k
m
−
m
n
{\displaystyle km-mn}
2
p
q
−
s
q
{\displaystyle 2pq-sq}
4
x
+
8
{\displaystyle 4x+8}
−
2
{\displaystyle -2}
5.
[
编辑
|
编辑源代码
]
6
x
3
y
2
{\displaystyle 6x^{3}y^{2}}
30
a
3
b
3
c
4
{\displaystyle 30a^{3}b^{3}c^{4}}
k
2
m
2
n
2
{\displaystyle k^{2}m^{2}n^{2}}
162
p
4
q
4
r
4
{\displaystyle 162p^{4}q^{4}r^{4}}
24
r
2
s
2
t
2
u
2
{\displaystyle 24r^{2}s^{2}t^{2}u^{2}}
6.
[
编辑
|
编辑源代码
]
b
c
{\displaystyle {b} \over {c}}
e
2
f
{\displaystyle {e} \over {2f}}
x
5
{\displaystyle {x} \over {5}}
2
a
{\displaystyle 2a}
2
p
r
{\displaystyle {2} \over {pr}}
7.
[
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编辑源代码
]
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
8.
[
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编辑源代码
]
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
9.
[
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{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
10.
[
编辑
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编辑源代码
]
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
11.
[
编辑
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编辑源代码
]
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
{\displaystyle }
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书籍:数学课本解答
华夏公益教科书